12^2+35^2=c^2

Solution for 12^2+35^2=c^2 equation:

12^2+35^2=c^2

We move all terms to the left:

12^2+35^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+1369=0

a = -1; b = 0; c = +1369;
Δ = b2-4ac
Δ = 02-4·(-1)·1369
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-74}{2*-1}=\frac{-74}{-2}
=+37
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+74}{2*-1}=\frac{74}{-2}
=-37
$